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10 questions from this quiz
cos2θ+sin2θ=1\cos^2 θ + \sin^2 θ = 1cos2θ+sin2θ=1
tanθ=sinθcosθ\tan θ = \frac{\sin θ}{\cos θ}tanθ=cosθsinθ
Side a
cosθ\cos θcosθ
Sine only
Two angles & a side OR two sides & non-included angle
Two sides & included angle OR all three sides
12bcsinA\frac{1}{2}bc \sin A21bcsinA
180°180°180°
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