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f(x)=∣ax+b∣f(x) = |ax + b|f(x)=∣ax+b∣, a≠0a \neq 0a=0
V-shaped
(−ba,0)\left(-\frac{b}{a}, 0\right)(−ab,0)
All real numbers (R\mathbb{R}R)
y≥0y \geq 0y≥0
Solve ax+b=0ax + b = 0ax+b=0
x=−bax = -\frac{b}{a}x=−ab
Two solutions
One solution
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