Combining Events (VCE SSCE Mathematical Methods): Quizzes

A set with no elements at all

As a rectangle

"or"

"and"

All elements in $\varepsilon$ not in $A$

When $A \cap B = \varnothing$

$\text{Pr}(A \cup B) = \text{Pr}(A) + \text{Pr}(B) - \text{Pr}(A \cap B)$

With the intersection and work outward

$\frac{3}{10}$

Adding $\text{Pr}(A)$ and $\text{Pr}(B)$ counts the intersection twice