Conditional Probability (VCE SSCE Mathematical Methods): Quizzes

The probability of A given B

Given or knowing that

$\frac{1}{3}$

No, order matters in conditional probability

$\frac{\text{Pr}(A \cap B)}{\text{Pr}(B)}$

$\text{Pr}(A \cap B) = \text{Pr}(A \mid B) \times \text{Pr}(B)$

Multiply along, add across

$0.28$

$\text{Pr}(A) = \text{Pr}(A \mid B)\text{Pr}(B) + \text{Pr}(A \mid B')\text{Pr}(B')$

$\frac{2}{3}$