Independent Events (VCE SSCE Mathematical Methods): Quizzes

$\text{Pr}(A | B) = \text{Pr}(A)$

$\text{Pr}(A \cap B) = \text{Pr}(A) \times \text{Pr}(B)$

No, because $0.2 \neq 0.5 \times 0.4$

$\text{Pr}(A \cup B) = \text{Pr}(A) + \text{Pr}(B)$

When $\text{Pr}(A) = 0$ or $\text{Pr}(B) = 0$

No, these concepts are incompatible

$0$

$\frac{1}{2}$

$0.1875$

Yes, as shown in the dice example