Exponential Growth and Decay (HSC SSCE Mathematics Advanced): Quizzes

$e^x$

$kQ$

$\frac{dP}{dt} = kP$

Value of $Q$ when $t = 0$

$M = M_0 e^{-kt}$

Time for half the substance to remain

$k = \frac{1}{10}\log_e 2$

$\frac{1}{2}$

$1760$ per year

$\frac{\log_e 10}{k}$