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10 questions from this quiz
logexlogea\frac{\log_e x}{\log_e a}logealogex
logea\log_e alogea
1xlogea\frac{1}{x \log_e a}xlogea1
y=logexy = \log_e xy=logex only
1logea\frac{1}{\log_e a}logea1
exlogeae^{x \log_e a}exlogea
axlogeaa^x \log_e aaxlogea
axlogea+C\frac{a^x}{\log_e a} + Clogeaax+C
Because logee=1\log_e e = 1logee=1
Differentiation
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