The Fundamental Theorem of Calculus (HSC SSCE Mathematics Advanced): Quizzes

$F'(x) = f(x)$

$\frac{x^6}{6} + C$

It requires dividing by zero

$F(b) - F(a)$

Expand to $x^2 + 3x$

Split into $x^3 - 3$

$\frac{3}{8}$

Function undefined at $x=0$ (asymptote)

Find primitive: $x^3$

Multiple terms prevent calculation errors