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10 questions from this quiz
Approximating solutions to diff. eqns.
The step length
The gradient at point (xr,yr)(x_r, y_r)(xr,yr)
Produces more accurate results
Above the curve
(approx. - exact) / exact
Uses average of 2 gradients
yr+12(k1+k2)y_r + \frac{1}{2}(k_1 + k_2)yr+21(k1+k2)
yr+1=yr−1+2hf(xr,yr)y_{r+1} = y_{r-1} + 2hf(x_r, y_r)yr+1=yr−1+2hf(xr,yr)
Use basic Euler to find y1y_1y1
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