Apply Differentiation Rules (HSC SSCE Mathematics Advanced): Quizzes

$\frac{dy}{dx} = \frac{dy}{du} \times \frac{du}{dx}$

When two functions are multiplied

$\frac{v\frac{du}{dx} - u\frac{dv}{dx}}{v^2}$

Chain rule

First × deriv. of 2nd + 2nd × deriv. of 1st

Bottom × top' - top × bottom', over bottom²

From outside in

The outermost operation

$0$

$y = -3x + 57$