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10 questions from this quiz
Situations where rates change at thresholds
Physical constraints limit possible values
2.50 USD
Additional distance beyond first km
18−2x18 - 2x18−2x cm
18−2x≥018 - 2x \geq 018−2x≥0 giving x≤9x \leq 9x≤9
12 cm
x9=12−y12\frac{x}{9} = \frac{12-y}{12}9x=1212−y
A(x)=2x(12−12x9)A(x) = 2x(12 - \frac{12x}{9})A(x)=2x(12−912x)
[0,9][0, 9][0,9]
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