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10 questions from this quiz
Apply 1 function, then another to result
fff is applied first
ran f⊆f \subseteqf⊆ dom ggg
dom fff
No, order matters
g∘f(x)=(2x−1)2g \circ f(x) = (2x - 1)^2g∘f(x)=(2x−1)2
Only g∘fg \circ fg∘f
ran ggg not subset of dom fff
Apply fff to xxx, then ggg to result
To make range fit next function's domain
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