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10 questions from this quiz
x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}x=2a−b±b2−4ac
Completing the square
x=2x = 2x=2 or x=−4x = -4x=−4
b24a2\frac{b^2}{4a^2}4a2b2
The discriminant
(x+1)2=9(x + 1)^2 = 9(x+1)2=9
x2+bax=−cax^2 + \frac{b}{a}x = -\frac{c}{a}x2+abx=−ac
There are two solutions
bbb and ccc
(x+b2a)2=b2−4ac4a2\left(x + \frac{b}{2a}\right)^2 = \frac{b^2 - 4ac}{4a^2}(x+2ab)2=4a2b2−4ac
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