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10 questions from this quiz
cos2θ+sin2θ=1\cos^2\theta + \sin^2\theta = 1cos2θ+sin2θ=1
1+tan2θ=sec2θ1 + \tan^2\theta = \sec^2\theta1+tan2θ=sec2θ
1+cot2θ=cosec2θ1 + \cot^2\theta = \cosec^2\theta1+cot2θ=cosec2θ
Divide by cos2θ\cos^2\thetacos2θ
When cosθ=0\cos \theta = 0cosθ=0
The x-coordinate
The more complicated side
secθ=1cosθ\sec \theta = \frac{1}{\cos \theta}secθ=cosθ1
sec2θ\sec^2\thetasec2θ
When sinθ=0\sin \theta = 0sinθ=0
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