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11 questions from this quiz
600 BC
Right-angled triangles
The longest side
Opposite the right angle
The hypotenuse
c=a2+b2c = \sqrt{a^2 + b^2}c=a2+b2
a=c2−b2a = \sqrt{c^2 - b^2}a=c2−b2
13 cm
8 cm
a=52−1.52a = \sqrt{5^2 - 1.5^2}a=52−1.52
Use Pythagoras with horizontal and vertical distances
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