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10 questions from this quiz
Numerator degree is one more than denominator
Where the denominator equals zero
y=x−1y = x - 1y=x−1
(0,3)(0, 3)(0,3)
No, because x2+3≠0x^2 + 3 \neq 0x2+3=0 for real xxx
1−4(x+1)21 - \frac{4}{(x + 1)^2}1−(x+1)24
x=1x = 1x=1 and x=−3x = -3x=−3
Local minimum at (1,2)(1, 2)(1,2)
Vertical asymptote at x=−1x = -1x=−1 splits domain
(−3,−6)(-3, -6)(−3,−6)
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