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10 questions from this quiz
Numerator degree is one more than denominator
Where the denominator equals zero
y=xโ1y = x - 1y=xโ1
(0,3)(0, 3)(0,3)
No, because x2+3โ 0x^2 + 3 \neq 0x2+3๎ =0 for real xxx
1โ4(x+1)21 - \frac{4}{(x + 1)^2}1โ(x+1)24โ
x=1x = 1x=1 and x=โ3x = -3x=โ3
Local minimum at (1,2)(1, 2)(1,2)
Vertical asymptote at x=โ1x = -1x=โ1 splits domain
(โ3,โ6)(-3, -6)(โ3,โ6)
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