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10 questions from this quiz
g(x)f′(x)−f(x)g′(x)[g(x)]2\frac{g(x)f'(x) - f(x)g'(x)}{[g(x)]^2}[g(x)]2g(x)f′(x)−f(x)g′(x)
For functions written as fractions
g(x)≠0g(x) \neq 0g(x)=0
g(x)f′(x)−f(x)g′(x)g(x)f'(x) - f(x)g'(x)g(x)f′(x)−f(x)g′(x)
[g(x)]2[g(x)]^2[g(x)]2
Product rule and chain rule
sec2θ\sec^2 \thetasec2θ
vdudx−udvdxv2\frac{v\frac{du}{dx} - u\frac{dv}{dx}}{v^2}v2vdxdu−udxdv
cosx\cos xcosx
2e2x2e^{2x}2e2x
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