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10 questions from this quiz
Approximate solutions to f(x)=0f(x) = 0f(x)=0
They must have opposite signs
m1=a1+b12m_1 = \frac{a_1 + b_1}{2}m1=2a1+b1
[a1,m1][a_1, m_1][a1,m1]
The error approximately halves
Degree 5 and higher
b−a>2×0.01b - a > 2 \times 0.01b−a>2×0.01
−1.29-1.29−1.29
Informal algorithm writing, structured
Function crosses x-axis where f(x)=0f(x)=0f(x)=0
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