6.3 – Determining Acceleration Due to Gravity Using a Simple Pendulum (Leaving Cert Physics): Flashcards

Find acceleration due to gravity (g)

$T = 2\pi\sqrt{\frac{l}{g}}$

Period (time for one complete oscillation)

Length of the pendulum

$T^2 = \frac{4\pi^2}{g} \times l$

$T^2$ (y-axis) vs length (x-axis)

$g = \frac{4\pi^2}{m}$

Fixed point to centre of bob

Reduces impact of human reaction time

Less than 10°

Close to $9.8 \, \text{m/s}^2$

Directly proportional ($T^2 \propto l$)

Simple harmonic motion

$\frac{4\pi^2}{g}$