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14 cards from this deck
Find acceleration due to gravity (g)
T=2πlgT = 2\pi\sqrt{\frac{l}{g}}T=2πgl
Period (time for one complete oscillation)
Length of the pendulum
T2=4π2g×lT^2 = \frac{4\pi^2}{g} \times lT2=g4π2×l
T2T^2T2 (y-axis) vs length (x-axis)
g=4π2mg = \frac{4\pi^2}{m}g=m4π2
Fixed point to centre of bob
Reduces impact of human reaction time
Less than 10°
Close to 9.8 m/s29.8 \, \text{m/s}^29.8m/s2
Directly proportional (T2∝lT^2 \propto lT2∝l)
Simple harmonic motion
4π2g\frac{4\pi^2}{g}g4π2
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