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12 questions from this quiz
Angle where refracted ray is at 90° to normal
n=1sinCn = \frac{1}{\sin C}n=sinC1
Higher refractive index = smaller angle
Semicircular glass block
Refracted ray emerges parallel to surface
Bends away from the normal
Flat-side down on paper
1.49
To improve reliability of results
From directly above
For precise marking and accuracy
When angle of incidence exceeds critical
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